5r^2-33r+150=)

Solution for 5r^2-33r+150=) equation:

5r^2-33r+150=)

We move all terms to the left:

5r^2-33r+150-())=0

We add all the numbers together, and all the variables

5r^2-33r=0

a = 5; b = -33; c = 0;
Δ = b2-4ac
Δ = -332-4·5·0
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-33}{2*5}=\frac{0}{10}
=0
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+33}{2*5}=\frac{66}{10}
=6+3/5
$